Question

factorise=y^3+y-30 please solve this question
​

Answer 1

Step-by-step explanation:

3y^+y-30=0

3y^+9y-10y-30=0

3y(y+3)-10(y+3)=0

(3y-10)(y+3)=0

this is factorise

and factorization method for given equation

(3y-10)(y+3)=0

3y-10=0 or y+3=0

3y=10. y=-3

y=10/3

Answer 2

Answer:

${3y}^{2} + {y}^{1} - 30$

${3y}^{2} - 9y + 10y -30$

$3y(y - 3) + 10(y - 3)$

$(3y + 10)(y - 3) = 0 \\ \\ therefore \: \: \: \: y = - 10 \div 3 \: and \: y = 3$

hope it helps!!

#BAL

#answerwithquality