Factorise -↓
y³ - 2y² - 29y - 42
Plz help me
Tomorrow is my exam
Answers
Answered by
7
HEY Buddy.....!! here is ur answer
Given that : y³–2y²–29y–42
=> y³+2y²–4y²–8y–21y–42
=> y²(y+2)–4y(y+2)–21(y+2)
=> (y+2)(y²–4y–21)
=> (y+2)(y²–7y+3y–21)
=> (y+2)[y(y–7)+3(y–7)]
=> (y+2)(y–7)(y+3)
I hope it will be helpful for you.....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Given that : y³–2y²–29y–42
=> y³+2y²–4y²–8y–21y–42
=> y²(y+2)–4y(y+2)–21(y+2)
=> (y+2)(y²–4y–21)
=> (y+2)(y²–7y+3y–21)
=> (y+2)[y(y–7)+3(y–7)]
=> (y+2)(y–7)(y+3)
I hope it will be helpful for you.....!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Answered by
1
don't know yrr__________sorry
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