Question

factorised the: a2+4a-5

Answer 1

$\large\fbox\red{Answer}$

${a}^{2} + 4a - 5 \\ \\ = {a}^{2} + (5 - 1)a - 5 \\ \\ = {a}^{2} + 5a - a - 5 \\ \\ = a(a + 5) - 1(a + 5) \\ \\ = (a + 5)(a - 1)$

• Thnku :)

Answer 2

Step-by-step explanation:

${a}^{2} + 4a - 5 \\ \\ {a}^{2} - 5a + 1a - 5 \\ \\ a(a - 5) + 1(a - 5) \\ \\ (a + 1) \: (a - 5)$