Question

Father is aged three times more than his son sunil.After 8 years, he would be two and a half times of sunil's age after further 8 years, how many times would he be sunil's age?

Answer 1

Assume that Sunil's present age =x
Then, father's present age =3x+x=4x
After 8 years, father's age =2 and a half times as that of Sunil's age
⇒(4x+8)= 2 and a half multiplied by (x+8)
⇒4x+8=5 upon 2 multiplied by (x+8)
⇒8x+16=5x+40
⇒3x=40−16= 24
⇒x=24 upon3= 8

After further 8 years,
Sunil's age =x+8+8=8+8+8=24
Father's age =4x+8+8=4×8+8+8=48

Father's age/Sunil's age =48 upon 24= 2

So, The answer is 2