Question

find 4th vertex of the square whose consecutive vertices are(2,1);(7,4);(-2,5)

Answer 1

let fourth vertex be x,y

as diagonals bisect
therefore mid point is same

2-2/2 = 7+x)/2 = 0 , x=-7

1+5)/2 = 4+y)/2 = 3
4+y = 6
y =2