Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively -1/4,3
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Answered by
3
sum of zeroes= -1/4
product of zeroes= 3
quadratic poly= x^2- (sum of zeroes) x + product of zeroes
= x^2- (-1/4)x+3
x^2+1/4x+3
4x^2+x+12
product of zeroes= 3
quadratic poly= x^2- (sum of zeroes) x + product of zeroes
= x^2- (-1/4)x+3
x^2+1/4x+3
4x^2+x+12
Answered by
4
Hi there !
Sum of zeroes = -1/4
Product of zeroes = 3
Quadratic polynomial is given by:-
k ( x² - [ sum of zeroes ] x + [ product of zeroes ] )
, here "k" is a constant.
x² - [-1/4 ]x + 3
= x² +1/4x + 3
to remove the fraction , we multiply the terms with 4
4[x² +1/4x + 3]
4x² + x + 12
4x² + x + 12 is the required polynomial.
Hope this helps you !!
Sum of zeroes = -1/4
Product of zeroes = 3
Quadratic polynomial is given by:-
k ( x² - [ sum of zeroes ] x + [ product of zeroes ] )
, here "k" is a constant.
x² - [-1/4 ]x + 3
= x² +1/4x + 3
to remove the fraction , we multiply the terms with 4
4[x² +1/4x + 3]
4x² + x + 12
4x² + x + 12 is the required polynomial.
Hope this helps you !!
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