Question

Find a two-digit number whose product of the digits is 8 and when 18 is added to this number, the digits are reversed..

Answer 1

Answer:

24

Step-by-step explanation:

Let the two digits be x and y respectively.

Since x is in the tens digit, let the number be (10x + y) and the reversed number be 10y + x.

According to the question,

xy = 8

10x + y + 18 = 10y + x

9x - 9y = -2

x - y = -2 -(i)

$x + y = \sqrt{(x - y) ^{2} + 4xy}$

Substituting all the values,

x + y = 6 -(ii)

By adding (i) and (ii),

x = 2

y = 4

Therefore, the number is 24 and the inversed number is 42.