find angle QPR
please answer......
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angle QPR=90
this is right answer bro
this is right answer bro
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PR=(100)^1/2=10
Now QR^2=26^2=676=24^2+10^2=QP&2+PR^2
SO ABIDING CONVERSE OF PYTHAGORAS THEOREM ANGLE QPR IS 90 DEGREE
Now QR^2=26^2=676=24^2+10^2=QP&2+PR^2
SO ABIDING CONVERSE OF PYTHAGORAS THEOREM ANGLE QPR IS 90 DEGREE
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