five years ago a man was seven times as old as his son. Five years hence, the ratio of their ages will be three times as old as his son. Find their present ages.
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Hello..
Answer...
Let the age of the son five years ago be =x
Therefore the age of the man =7x
The present age of the son =x+5
The present age of the man =7x+5
The age of the son after five years =x+5+5=x+10
The age of the man after five years 7x+5+5=7x+10
According to the question
7x+10=3(x+10)
7x+10=3x+30
7x-3x=30-10
4x=20
x=20/4=5
Therefore the present age of the son =x+5=5+5=10 years.
man's age =7x+5=7 multiplied by 5+5=40 years.
Hope it helped ☺ ☺ ☺
Answer...
Let the age of the son five years ago be =x
Therefore the age of the man =7x
The present age of the son =x+5
The present age of the man =7x+5
The age of the son after five years =x+5+5=x+10
The age of the man after five years 7x+5+5=7x+10
According to the question
7x+10=3(x+10)
7x+10=3x+30
7x-3x=30-10
4x=20
x=20/4=5
Therefore the present age of the son =x+5=5+5=10 years.
man's age =7x+5=7 multiplied by 5+5=40 years.
Hope it helped ☺ ☺ ☺
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