Math, asked by princy212, 11 months ago

Find arithmetic Progression whose third term is 16 and the seventh term exceeds the 5th term by 12.

Answers

Answered by Anonymous

3

t3 =a+2d=16

given, t7=t5+12

a+6d-(a+4d)=12

2d=12

d= 6

substituting d in t3,

we get ,

a=4

thus a.p will be,

a,a+d,a+2d,.........

A.P= 4,10,16,........

princy212: thank you very much

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