Find Compound Interest on Rs.6000 for 2 years at the rate of 10 p.c.p.a.
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Given that Principal = 6000, n = 2 years, r = 10% per annum.
We know that A = P(1 + r/100)^n
= 6000(1 + 10/100)^2
= 6000(1 + 1/10)^2
= 6000(1 + 10/10)^2
= 6000(11/10)^2
= 6000 * 121/100
= 60 * 121
= 7260.
We know that Compound Interest = Amount - Principal
= 7260 - 6000
= 1260.
Therefore the compound interest = 1260 rupees.
Hope this helps!
We know that A = P(1 + r/100)^n
= 6000(1 + 10/100)^2
= 6000(1 + 1/10)^2
= 6000(1 + 10/10)^2
= 6000(11/10)^2
= 6000 * 121/100
= 60 * 121
= 7260.
We know that Compound Interest = Amount - Principal
= 7260 - 6000
= 1260.
Therefore the compound interest = 1260 rupees.
Hope this helps!
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