Question

find f(√2),if f(x)=x^2 +√2x+1.​

Answer 1

f(√2) = (√2)^2 + √2 × √2 + 1

= 2 + 2 + 1

= 5

i hope it helps

Answer 2

Hey

$f(x) = x {}^{2} + \sqrt{2} x + 1 \\ \\ given \: that \\ f(x) = f( \sqrt{2} ) \\ \\ = > f( \sqrt{2} ) = ( \sqrt{2} ) {}^{2} + \sqrt{2} ( \sqrt{2} ) + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 + 2 + 1 = 5$