Find k if kx+3y+1=0 and 2x+y+3=0 has unique solution
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kx + 3y + 1 = 0
2x + y + 3 = 0
For unique solution,
a1/a2 ≠ b1/b2
=>k/2 ≠ 3/1
=> k ≠ 3 × 2
=> k ≠ 6
Hope it'll help...
2x + y + 3 = 0
For unique solution,
a1/a2 ≠ b1/b2
=>k/2 ≠ 3/1
=> k ≠ 3 × 2
=> k ≠ 6
Hope it'll help...
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