Physics, asked by prutha23, 1 year ago

find percentage error in volumr of sphere of radius 2%

Answers

Answered by Anonymous
1
Your answer is --

Given, % error in radius of sphere ∆r = 2%

Volume of sphere = 4πr^3

4π is constant

Let, volume error be ∆V

Therefore ,

∆V/V×100 = (3×∆r/r)×100

=> ∆V/V×100 = 3×2

=> ∆V/V×100 = 6%


Hence, %error in its volume is 6%


Hope it helps you
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