find percentage error in volumr of sphere of radius 2%
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Given, % error in radius of sphere ∆r = 2%
Volume of sphere = 4πr^3
4π is constant
Let, volume error be ∆V
Therefore ,
∆V/V×100 = (3×∆r/r)×100
=> ∆V/V×100 = 3×2
=> ∆V/V×100 = 6%
Hence, %error in its volume is 6%
Hope it helps you
Given, % error in radius of sphere ∆r = 2%
Volume of sphere = 4πr^3
4π is constant
Let, volume error be ∆V
Therefore ,
∆V/V×100 = (3×∆r/r)×100
=> ∆V/V×100 = 3×2
=> ∆V/V×100 = 6%
Hence, %error in its volume is 6%
Hope it helps you
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