find perimeter of rectangle whose length is 40cm and diagonal 41cm
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Answered by
29
Using Pythagoras Theorem
b=9cm
perimeter=2(l+b)=2(40+9)=2×49=98cm
b=9cm
perimeter=2(l+b)=2(40+9)=2×49=98cm
Answered by
10
by pythagoras theorem
perimeter 2(l+b)= 2 (40+9) =2×49=98
perimeter 2(l+b)= 2 (40+9) =2×49=98
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