Question

Find real numbers x and y such that
3x + 2iy – ix + 5y = 7 + 5i.​

Answer 1

Answer:

3x+5y-xi+2yi=7+5i

comparing,

3x+5y=7 ....1 eq

-x+2y=5...2eq

multiply eq2 by 3

-3x+6y=15......3eq

adding eq 1 and2

x=39 and y=22.

Answer 2

Answer:

y= 5/11,x = -39/11

Step-by-step explanation:

3x + 2iy – ix + 5y = 7 + 5i

Or, 3x +7 + 5y= 5i + ix - 2iy

3x +7 + 5y +0i = 0+i(5+x-2y)

So, 3x +7 + 5y = 0

&. 5+x=2y

So, y = 8/11 & x = -39/11