find remainder theorem when
x4+x3+2x2+x+1 is divided by x-1
remainder theorem
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6
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zaidfahimshaikh:
Hmm
Answered by
4
Answer:
P(x)= 4x+3x + 2×2+x+1
g(x)= x-1
therefore zero of the g(x) is
x-1=0⇒x=1
P(1)=4×1+3×1 +2×2+1+1
P(1)=4+3+4+2
p(1)=13
Step-by-step explanation:
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