find the 6th term from the end of the Ap 5,2,-1,-4,-----,-31
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Answered by
17
Given: The arithmetic progression 5, 2, -1, -4, .........., -31
To find: The 6th term of the Arithmetic Progression.
Solution:
- Now we have given the arithmetic progression 5, 2, -1, -4, .........., -31.
- The first term a is 5.
- The common difference is 2 - 5 = -4 - (-1) = -3.
- The last term is -31.
- Now the sixth term of the Arithmetic Progression will be:
a + 5d
- So putting the values in the sixth term, we get:
5 + 5(-3)
5 - 15
-10
Answer:
So the sixth term of the arithmetic progression 5, 2, -1, -4, .........., -31 is -10.
Answered by
3
Let, a1=5, a2=2, a3 = -1 and an= -31
so d= a2 -a1=2-5= -3
then the nth term => an =a+(n-1)×d
=> -31= 5+(n-1)× -3
=> -31=5-3n+3
=> -3n= -31-8
=> n= -39/-3
=> n=13
so there are 13 term given AP
the 6th term from the end will be the 8th term
=> a8=a+(n-1) ×d
=> a8=5+(8-1) × -3
=> a8=5+7× -3
=> a8 = -16
the 6th term from the last term is -16
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