Question

find the amount and compound interest on 24,000 compounded semi-annually for 3/2 years at the rate of 10%p.a

Answer 1

P= 24,000  n = 3 (because due to semi annually  3 x 1/2 months are there)
r = 10% but for 1/2 years r = 10/2 = 5%

formula for Amount =  P (1 + r      )^n
                                                __
                                                 100

                                = 24000 (1+0.05)^3
                                = 24000* 1.05*1.05*1.05
                                 = Rs.27783
  Interest = A - P
                = 27783 - 24000
                = Rs. 3783

Answer 2

Step-by-step explanation:

a =p( 1+r/100)power n

a= 24000(1+5/100) power 3

= 24000( 20/20+1/20) power 3

= 24000× 21/20× 21/20×21/20

= 6×21×21×21

=

126×431

54306 answer