Question

find the amount of Rs 8000 for 3years commounded annually at 5%per annum
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Answer 1

Given :

• Sum of Rs.8000 is for 3 years compounded annually at 5% per annum .

To Find :

• Amount at the end of 3 years .

Solution :

$\longmapsto\tt{Principal\:(P)=Rs.8000}$

$\longmapsto\tt{Time(t)=3\:yrs.}$

$\longmapsto\tt{Rate(r)=5\%}$

Using Formula :

$\longmapsto\tt\boxed{Amount=P\bigg(1+\dfrac{r}{100}\bigg)^{t}}$

Putting Values :

$\longmapsto\tt{8000\bigg(1+\dfrac{5}{100}\bigg)^{3}}$

$\longmapsto\tt{8000\bigg(\dfrac{100+5}{100}\bigg)^{3}}$

$\longmapsto\tt{8000\bigg(\dfrac{105}{100}\bigg)^{3}}$

$\longmapsto\tt{8{\not{0}}{\not{0}}{\not{0}}\times\dfrac{1157625}{1000{\not{0}}{\not{0}}{\not{0}}}}$

$\longmapsto\tt{\dfrac{8\times{1157625}}{1000}}$

$\longmapsto\tt{\dfrac{9261000}{1000}}$

$\longmapsto\tt\bf{Rs.9261}$

So , The Amount at the end of 3 years will be Rs.9261 .

_______________________

• $Amount=P\bigg(1+\dfrac{r}{100}\bigg)^{t}$

• Compund Interest = Amount - Principal
• Simple Interest = P × T × R /100

Here :

• P = Principal
• T = Time
• R = Rate of Interest

_______________________

Answer 2

Step-by-step explanation:

Given :

• Principle = 8000 Rs

• Time = 3 years

• Rate = 5 %

To Find :

• Find the amount

Solution :

Concept :

• Use this simple interest calculator to find A, the Final Investment Value, using the simple interest formula: A = P(1 + rt) where P is the Principal amount of money to be invested at an Interest Rate R% per period for t Number of Time Periods. Where r is in decimal form; r=R/100; r and t are in the same units of time.

We have :

$: \implies \: \: \: \boxed{ \sf \: A = P \bigg \{1 + \frac{R}{100} \bigg \} ^{T} }$

Substitute all Values :

$: \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A= 8000 \bigg \{1 + \frac{5}{100} \bigg \} ^{3} \\ \\ \\ : \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A= 8000 \bigg \{ \cancel{\frac{105}{100}} \bigg \} ^{3} \\ \\ \\ : \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A= 8000 \bigg \{ \frac{21}{20} \bigg \} ^{3} \\ \\ \\ : \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A= 8000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \\ \\ \\ : \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A=\cancel{8000} \times \frac{21 \times 21 \times 21}{\cancel{8000}}$

$: \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A=21 \times 21 \times 21 \\ \\ \\ : \implies \: \: \: \sf \: \: \: \: \: \: \: \: \: \: \: A = 9261$

• $\therefore \: \: \underline{ \sf \: the \: amount \: is \: 9261} \:$