Question

Find the area and side of a square, the length of whose diagonal is 72 cm

Answer 1

Hello...

Area of square = {(Diagonal)^2}÷2

= (72×72)÷2 sq. cm.

= 5184÷2 sq. cm.

= 2592 sq. cm Answer

Answer 2

$diagonal \: of \: square = 72cm$

$we \: know \: that$

$area \: of \: square = \frac{ {(diagonal)}^{2} }{2}$

$area \: of \: square = \frac{ {72}^{2} }{2}$

$area \: of \:square = \frac{5184}{2}$
therefore,

$area \: of \: square = 2592 {cm}^{2}$

$we \: know \: that$

$area \: of \: square = {(side)}^{2}$

$2592= {(side)}^{2}$

by taking square root to both sides

we get,


$36 \sqrt{2}cm = side \: of \: square$
therefore,

the area of square is 2592 sq .cm and side is 36√2 cm.

$hope \: this \: helps$