Question

find the area of a triangle field whose sides are 30m, 40m and 50m. also, find the length of ?​

Answer 1

Answer:

area = √s(s-a)(s-b)(s-c)

where s = (a+b+c)/2

s = (30+40+50)/2 = 60

area = √(60*30*20*10)

= √ 360000

= 600

altitude to longest side

= (2*600)/50 = 1200/50

= 24

Hope this is helpful for you.

Answer 2

Answer:

$\color{purple}{given-that}$

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triangle first side=30m.

triangle second side=40m.

triangle third side=50m.

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$\color{purple}{find-that}$

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we know area find triangle formula=

$\color{purple}{√s(s-a)(s-b)(s-c)}$

where

$\color{red}{s=a+b+c/2}$

s=30+40+50/2

s=120/2

s=60m.

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$\color{purple}{to-solve}$

=√60(60-30)(60-40)(60-50)

=√60×30×20×10।

=√30×30×2×2×10×10

=30×2×10

=600m.$\color{purple}{ANWER}$

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altitude to longest side

=2×600/50

=24$\color{orange}{ANWER}$

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