find the area of triangle whose sides are 8cm and 11cm and the perimeter is 32cm
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48.3cm square
Step-by-step explanation:
s=a+b+c/2
P= a+b+c
A= root s(s-a) (s-b) (s-c)
A= 1/4 root 32 square + 4.32 cube. 8 + 4.(32.8) square - 12.32 square. 8 .11 .4. (32.11) square +8 . 3
= 43.8178 cm square
(some points in between mean ×
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