Question

find the common difference of an AP whose first term is 4 and last term is 49 and the sum of all its term is 265

Answer 1

The common differences is 3

Answer 2

Answer:

5

Step-by-step explanation:

here is the answer

let first term is a and difference is and total terms are n then

a=4

a+(n-1) d=49

(n-1) d=49-4=45--->1

sum of n terms is 265

then

n×{2a+(n-1) d}=265×2---->2

put value in eq. 2

then we get

n×(8+45) =530

n×53=530

n=10

then

(n-1) d=45

9×d=45

d=5