Question

Find the common difference of an AP whose first term is 5 and 12th term is 137​

Answer 1

Answer:

12.

Step-by-step explanation:

Given:

a1 = 5

a12 = 137

n=12

To find:

d

Proof:

$a_{n} = a_{1} +(n - 1)d$

On substituting the values we have,

$137 = 5 + (12 - 1)d$

$11d = 132$

$d = \frac{132}{11}$

$d = 12$

Therefore, the required common difference is 12.

Hope it helps you.

Good Luck.

Answer 2

Given: a=5,a12=137

To find: common differnce

Solution:

WKT, nth term = a + (n-1)d

a12= 5 + (12-1)d

137= 5+ 11d

11d= 137-5

11d= 132

d= 132/11

d=12

Therefore common differnce = 12