Question

find the compound interest on 6000 rupees at 20% per annum compounded annually for 2 year full solved answer question

Answer 1

the given rupees is 6000 then
it's 10%=600
for 1st year 6000 + 1200 =7200
for 2nd year 7200 + 1440=8640

Answer 2

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Principal : ₹ 6000
Rate of interest : 20 % per annum
: 10 % annually
Time period : 2 years
: 1 half year

$amount \: = p(1 + \frac{ r}{100}) {}^{1}$

$a \: = 6000(1 + \frac{10}{100} ) {}^{1}$

$amount \: = p(1 + \frac{ 100 + 10}{100} ) {}^{1}$

$amount \: = 6000( \frac{110}{100} ) {}^{1}$

$amount \: = 6000 \times ( \frac{11}{10} ) {}^{1}$

amount = ₹6600
compound interest = amount + principal
= ₹ 6600 + ₹ 6000
= ₹ 12600...
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