Find the cubic polynomial with the sum ,sum of the product of it's zeroes taken at a time, and product of it's zeroes as 3,-1,-3 respectively
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here,
a=3
B=-1
c=-3
a+b+c = 3+(-1)+(-3)= -1= -b/a
ab+bc+ca= 3(-1)+ (-1)-3+ 3(-3)= -9 = c/a
abc = 3(-1)(-3) = 9 = -d/a
cubic polynomial:
x^3- x^2 -9x + 9
a=3
B=-1
c=-3
a+b+c = 3+(-1)+(-3)= -1= -b/a
ab+bc+ca= 3(-1)+ (-1)-3+ 3(-3)= -9 = c/a
abc = 3(-1)(-3) = 9 = -d/a
cubic polynomial:
x^3- x^2 -9x + 9
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