Math, asked by fahiya83, 5 months ago

Find the difference between simple and compound interest on 500 for 2 years at 8 %p.a​

Answers

Answered by itsbrainlybiswa
10

Answer:

ANSWER

Given

P=Rs.8500,R=6%,n=2 yrs

We know that amount A at the end of n years at the rate R % per annum when the interest is compounded annually is  

A=P(1+  

100

R

​  

)  

n

 

=8500(1+  

100

6

​  

)  

2

 

=8500(  

100

106

​  

)  

2

=  

100

85×106  

2

 

​  

=0.85×106  

2

 

=Rs. 9550.6

Also  CI=A−P=9550.6−8500.0=Rs1050.6

We know that SI=  

100

PRT

​  

 

=  

100

8500×6×2

​  

=Rs1020

∴ Difference between CI and SI

CI−SI=9550.6−1020.0=Rs.8530.6

Step-by-step explanation:

Answered by itzBrainlystarShivam
2

\Huge\boxed {r.s=3.2}

\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}} \\

p = rs.500

r = 8\%p.a.

t = 2 \: years.

\Large{\textsf{\textbf{\underline{\underline{To.find\::}}}}} \\

●diffrence \: between  \\ \: ci \: and \: si

\Large{\textsf{\textbf{\underline{\underline{formulas.used\::}}}}} \\

si =  \frac{prt}{100}

A = p \:   (1 +  \frac{r}{100} )t

c.i = a-p

\Large{\textsf{\textbf{\underline{\underline{solusion\::}}}}} \\

{\bf{1.case\::}} \\

➣to \: find \: s.i.

➣we \: know, \:

➣s.i. =  \frac{p \times r \times t}{100}

➣s.i. =  \frac{500 \times  8 \times 2}{100}

\small{\textsf{\textbf{\underline{\underline{ ➣s.i = 80\::}}}}} \\

{\bf{2.case\::}} \\

➣to \: find \: ci,

➣we \: know, \:

➣A = p(1 +  \frac{r}{100} )t

➣a = 500(1 +  \frac{8}{100} ) {}^{2}

➣a = 500(100 +  \frac{8}{100} ) {}^{2}

➣a = 500( \frac{108}{100} ) {}^{2}

➣a = 500  \times  \frac{108}{100} \times  \frac{108}{100}

\small{\textsf{\textbf{\underline{\underline{➣A = 583.2\::}}}}} \\

{\bf{3.case\::}} \\

➣to.find.c.i

➣we.know. c.i = A - p

➣c.i = 583.2 - 500

\small{\textsf{\textbf{\underline{\underline{➣c.i = 83.2\::}}}}} \\

\small{\textsf{\textbf{\underline{\underline{now.finding.the.diffrence.between.ci.and.si\::}}}}} \\

➣c.i = 83•2

➣s.i = 80

➣difference = r.s  (83.2 - 80)

\Large{\textsf{\textbf{\underline{\underline{➣r.s = 3.2\::}}}}} \\

\Large{\textsf{\textbf{\underline{\underline{form.the.soluaion\::}}}}} \\

●p = principal \\ ●r = rate \: of \: interest \\ ●t = time \\ ●si = simple \: interest \\ ●ci  = compound \: interest \\ ●a = amount

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