Find the difference between two numbers if first is 6 times of second and sum of them is 63
Answers
Answered by
30
6x + x = 63
7x = 63
x = 63/7
x = 9
First Number = 9 × 6
= 54
Second Number = 9
Their Difference-
54 - 9 = 45
7x = 63
x = 63/7
x = 9
First Number = 9 × 6
= 54
Second Number = 9
Their Difference-
54 - 9 = 45
Answered by
17
Let the second number be x.
∴The second number is 6x.
Their sum is 63:
6x + x = 63
∴7x = 63
∴x = 63/7
∴x = 9
∴The First Number = 6x = 6*9 = 54
The Second Number = x = 9
∴Difference = 54-9 = 45
Thus, difference of the two numbers is 45.
∴The second number is 6x.
Their sum is 63:
6x + x = 63
∴7x = 63
∴x = 63/7
∴x = 9
∴The First Number = 6x = 6*9 = 54
The Second Number = x = 9
∴Difference = 54-9 = 45
Thus, difference of the two numbers is 45.
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