Find the domain and range of the real function f(x)=√9-x^2
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Here we have,
f(x) = √9 - x²
Here,
f(x) is not defined when the value of (9 - x²)<0
As,
f(x) is defined when the value of (9 - x²)≥0
So,
(9 - x²) ≥ 0
x² - 9 ≤ 0
x² ≥ -3
-3 ≤ x ≤ 3
x € [-3 , 3]
Therefore,
dom (f) = [-3 , 3]
Here,
For each
x € [-3 , 3]
f(x) = √9 - x² have value in interval [0,3].
Therefore,
Range (f) = [0,3]
So,
dom (f) = [-3 , 3] also range (f) = [0 , 3]
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