Find the sum of all natural numbers between 100 and 1000
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AP: 101, 102,....999
Here, a=101, d=1, an=l=999
As, an=a+(n–1)d
so, 999=101+(n–1)
n=899
as, Sn=n/2(a+l)
=899/2(101+999)
=889×550
=4,88,950
So, the sum of all the natural numbers between 100 and 999 is 488950
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