Find the equation to the diagonals of a rectangle whose sides are x+1=0, y-4=0, y+1=0 and y-2=0. (if the answer is given is good then... Brainliest mark )
KAS11:
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Answers
Answered by
94
Sides of the rectangle: x-1 = 0 x-4 = 0
y+ 1 = 0 y-2 = 0
Vertices are : A (1, -1), B (1,2 ) , D (4, -1) , C (4, 2)
diagonal AC: (y+1)/(x-1) = (2 - (-1))/ (4-1) = 1
y = x - 2
diagonal BD: (y-2)/(x-1) = (-1-2)/(4-1)
y = -x +3
y+ 1 = 0 y-2 = 0
Vertices are : A (1, -1), B (1,2 ) , D (4, -1) , C (4, 2)
diagonal AC: (y+1)/(x-1) = (2 - (-1))/ (4-1) = 1
y = x - 2
diagonal BD: (y-2)/(x-1) = (-1-2)/(4-1)
y = -x +3
click on red heart thanks above
good ans
i clicked
But @Kvnmurthy .... Can we use (y-y1)=m(x-x1) ???
yes. that is what i used above for equations of the diagonals
Ok thanks
@kvnmurthy
Answered by
6
Answer:
Sides of the rectangle: x-1 = 0 x-4 = 0
y+ 1 = 0 y-2 = 0
Vertices are : A (1, -1), B (1,2 ) , D (4, -1) , C (4, 2)
diagonal AC: (y+1)/(x-1) = (2 - (-1))/ (4-1) = 1
y = x - 2
diagonal BD: (y-2)/(x-1) = (-1-2)/(4-1)
y = -x +3
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