Question

Find the equivalent resistance of the following circuit between junction A and B.

Answer 1

Answer:

Explanation:

Rs1=R1+R2                          Rs2=R3+R4

   =2+10                                 =3.5+2.5

    =12 ohm                            =6 ohm

now,Rs1,Rs2 and 4ohm are connected in parallel

hence,

1/Rp=1/12+1/4+1/6

      =1/2

total resistance btw A and B is 2 ohms

Answer 2

Answer:

Answer in attachment

In 1st case

R eff = 2+10) ohm=12ohm

And in second case

R eff = 2.5+3.5=6ohm

And the three are in parallel

So 1/r eff = 1/12+1/4+1/6 = 6/12=1/2ohm

Therefore total resistance =2ohm.

Explanation: