Question

Find the gradient of the straight line passing through the points (6,-2) and (2,-1)

Answer 1

Answer :

The required gradient is -1/4

Given :

• The points are (6 , -2) and (2 , -1)

To Find :

• The gradient of the line joining the given points.

Formula to be used :

$\sf{If \: \: (x_{1} , y_{1}) \: \: and \: \: (x_{2} , y_{2}) \: \: are \: \: two \: \: points \: \: then \: \: the \: \: gradient \: \: of \: \: the \: \: line \: \: joining \: \: these \: \: points \: \: is}$

$\sf{Gradient , \: m = \dfrac{y_{2} -y_{1}}{x_{2} - x_{1}} }$

Solution :

Thus , gradient of the line joining the points (6,-2) and (2,-1) is given by ,

$\sf{\implies m = \dfrac{-1-(-2)}{2-6}}\\\\ \sf{\implies m = \dfrac{-1 + 2}{-4}}\\\\ \sf{\implies m=-\dfrac{1}{4}}$

Extra information :

Gradient or slope of a line :

• Definition : The tangent of the angle formed by a line with positive direction of X-axis measure lf anti-clockwise is called the gradient or slope of the line .
• Gradient of a line l, whose inclination is θ is given by ,m= tanθ

Answer 2

Answer :

The required gradient is -1/4

Step-by-step explanation:

gradient of the line joining the points (6,-2) and (2,-1) is given by

=> m = -1 - ( - 2)/ 2 - 6

= 1 / -4

= -1/4

=> m = -1/4