Find the HCF a^2-b^2-2a+1 and a^2-ab-a
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Answer:
First expression = x2 - 3x - 18
= x2 - 6x + 3x - 18, by splitting the middle term - 3x = - 6x + 3x
= x(x - 6) + 3(x - 6)
= (x - 6) (x + 3)
Second expression = x2 + 5x + 6
= x2 + 3x + 2x + 6, by splitting the middle term 5x = 3x + 2x
= x(x + 3) + 2(x + 3)
= (x + 3) (x + 2)
Step-by-step explanation:
Therefore, in the two polynomials (x + 3) is the only common factors, so, the required H.C.F. = (x + 3).
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