Find the hcf of 504 and 1188 using euclids algorithm
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Solution:
Euclid's Algorithm:
Let a and b be any two positive
integers .Then there exit two unique whole numbers q and r
such that
a = bq + r ,
0≤ r<b
Here , a is called the dividend,
b is called the divisor , q is called the quotient and r is called the remainder.
Now ,
Given 504 and 1188.
Start with the larger integer, that is 1188.
Apply the division algorithm to
504 and 1188
1188 = 504 × 2 + 180
Since , the remainder 180≠0, we apply the division algorithm to 180 and 504
504 = 180 × 2 + 144
similarly,
180 = 144 × 1 + 36
144 = 36 + 4 + 0
The remainder has now become zero , so our procedure stops.
Since , the divisor at this stage
is 36 ,
the HCF of 504 and 1188
is 36.
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