Find the heat needed to convert 10g of ice at 0 celsius to water at 20 celsius.
Given: Latent heat of fusion of ice=
j/kg; specific heat of water= 4200 J/kg-k.
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10g=0.01kg
For converting 0 degrees ice to 0 degree water the amount of heat is
Q=mlf
=0.01*336000
=3360
For converting 0 degrees water to 20 degrees water is
Q=mass*specific heat*temparature difference
=0.01*4200*(20-0)
=840
Total heat =3360+840
=4200
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