find the height of a Trapezium whose area is 10812 square and the length of its parallel sides are 55.6 cm and 34.4 CM
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area=1/2(sum of parellel sides)*distance btwn them
1080=1/2(55.6+34.4)*height
height=(1080*2)/90
height=24cm.
1080=1/2(55.6+34.4)*height
height=(1080*2)/90
height=24cm.
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Area of trapezium = 1/2*(sum of parallel sides) *distance between them
where distance between them is the height = H
10812 = (1/2)*(55.6+34.4)*H
10812 = (1/2)*90*H
10812 = 45*H
H = 10812/45
H = 240.267 cm
where distance between them is the height = H
10812 = (1/2)*(55.6+34.4)*H
10812 = (1/2)*90*H
10812 = 45*H
H = 10812/45
H = 240.267 cm
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