Question

find the largest number which divide 615 and 963 leaving remainder 6 in each case.

Answer 1

HYE

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we have to  find the largest number which divide 615 and 963 leaving remainder 6 in each case.

let the hcf be A

=> so let us subtract 6 fom both the cases

=>615 - 6 = 609

=> 963-6 = 957
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now lets find the hcf 


=>prime factorisation of 609 = 29*3*3

prime factoristaion of 957 = 29*3*11

now lets take out the common factors from both the cases

=> 29 and 3

x = 29 * 3 = 87

∴87 is the number which will divide 615 and 963 leaving remainder 6 in each case.

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hope it helps u.........

Answer 2

Answer:

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