Math, asked by nahidasadek2, 1 month ago

find the least number which when divided by 15 and 21 leaves a remainder 6 in each case

Answers

Answered by erpankajrai1
1

Answer:

3

Step-by-step explanation:

for finding the least nunber which when divided by 15 and 21 leaves remainder 6 in each case . we will subtract 6 from both number so 15-6=9 and 21-6=15

so now my Euclid division lemma

15=9×1+6

9=6×1+3

6=3×2+0

so 3 is the answer

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