find the least number which when divided by 15 and 21 leaves a remainder 6 in each case
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1
Answer:
3
Step-by-step explanation:
for finding the least nunber which when divided by 15 and 21 leaves remainder 6 in each case . we will subtract 6 from both number so 15-6=9 and 21-6=15
so now my Euclid division lemma
15=9×1+6
9=6×1+3
6=3×2+0
so 3 is the answer
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