Question

find the mass of an ice cube of edge 2 cm. The density of ice = 900 kg/m3

Answer 1

density=mass/volume
volume can be obtained by given 2cm=0.02m edge so (l×l×l)we will multiply 0.02×0.02×0.02=0.000008(cubic meter)
so mass will be:
900=mass/0.000008
mass=900×0.000008
mass=0.0072kg

Answer 2

Mass of the ice cube will be 0.0072 kg or 0.72 g

Given:

Edge of ice cube= 2cm

Density of ice cube= 900 kg/$m^{3}$

In order to find the mass of the ice cube, we will use the following formula:

Density=$\frac{mass}{volume}$

Thus, Mass= Density × Volume

Volume of a cube=$edge^{3}$

Therefore, volume of ice cube will be $2^{3}$= 8 $cm^{3}$

We will convert the density into kg/ $cm^{3}$

$\frac{900kg}{1000000000cm^{3} }$

Now, mass of the ice cube will be

Density of the ice cube × Volume of the ice cube

$\frac{900}{1000000000}$ × 8= 0.0072 kg or 0.72 g

Thus, mass of the ice cube will be 0.0072 kg or 0.72 g

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