Find the minimum value of 3cosx+4sinx+5. Please do it fast... I will definitely mark the best as brainliest
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f(x) = 3cosx + 4sinx + 5
f '(x) = -3sinx + 4cosx
0 = -3sinx + 4cosx
3sinx = 4cosx
tanx = 4/3
x = 0.927 + npi radians for all integers, n
f ''(x) = -3cosx - 4sinx
f ''(0.927) = -5 < 0 so a maximum occurs at x = 0.927
f ''(0.927 + pi) = 5 > 0 so a minimum occurs at x = 4.069
f(0.927 + pi) = f(4.069) = 0
f '(x) = -3sinx + 4cosx
0 = -3sinx + 4cosx
3sinx = 4cosx
tanx = 4/3
x = 0.927 + npi radians for all integers, n
f ''(x) = -3cosx - 4sinx
f ''(0.927) = -5 < 0 so a maximum occurs at x = 0.927
f ''(0.927 + pi) = 5 > 0 so a minimum occurs at x = 4.069
f(0.927 + pi) = f(4.069) = 0
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