Find the moment of inertia of the circular ring of mass 2 kg and radius 0.5m along axis of centre of mass.
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Given : m = 2kg
r = 0.5m
Moment of inertia = m(r x r)
. = 2(0.5 x 0.5)
. = 2(0.25)
. = 0.5
r = 0.5m
Moment of inertia = m(r x r)
. = 2(0.5 x 0.5)
. = 2(0.25)
. = 0.5
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