Question

find the number of tiles needed to cover a floor of length 18 m and breath 9cm if each tile measures 20cm by 10 cm​

Answer 1

Answer:

300 tiles

Step-by-step explanation:

Length of floor = 4 metres

breadth of the floor = 3 metres

Area of the floor = 4m * 3m = 12 sq.m

lenght of the tile = 20cm

area of the tile = 20 * 20 = 400cm^2

12 sq. m = 120000 sq. cm

no.of tiles required = 120000/400 = 300 tiles

therefore, you require 300 tiles to cover your floor

Hope it helps :)

Answer 2

Answer:

length of floor. 18m

breadth of floor. 9m

Area of floor. length* breadth

18m * 9m

162m²

we know that,

1m = 1000cm

162m= 1000*162

= 162000cm²

length of tiles 20cm

breadth of tiles. 10 cm

Area of tiles. length * breadth

200cm²

no. of tiles needed to cover room= Area of floor / Area of tiles

162000cm² / 200cm²

810 tiles are required to cover a floor

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