Question

find the number such that the prodct of its preceding and succeeding numbers is 24 ?​

Answer 1

Answer:

Let the no be = x

preceding no. = x-1

succeeding bo.= x+1

product

(x-1) (x+1) = 24

x^2+x-x-1 = 24

x^2= 25

x=√25

x=5

Answer 2

Answer:

number = x

successor = x+1

precedessor - x-1

product = 24

(x+1)(x-1) = 24

identity = (a-b)(a+b) = a^2 -b^2

(x)^2 -(1)^2 = 24

x^2 -1 = 24

x^2 = 24+1

x^2 = 25

x= √25

x= 5

therefore number required= 5