find the perimeter of the rectangle where dimensions are zero values of quadratic polynomial x square -7x +12
Answers
Answered by
3
p(x)=x^2-7x+12
=(x-3)(x-4)
hence
x=3 or x=4
now the perimeter of rectangle =
2(l+b)
=2(3+4)
=2(7)
=14
hope this would help you
=(x-3)(x-4)
hence
x=3 or x=4
now the perimeter of rectangle =
2(l+b)
=2(3+4)
=2(7)
=14
hope this would help you
Similar questions