Question

Find the perimeter of the rectangle whose length is 15 cm and a diagonal is 17 cm.
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.Give answer with full explanation
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Answer 1

Answer:

P=2(l+w)

d=w2+l2

Solving forP

P=2l+2d2﹣l2=2·15+2·172﹣152=46cm

Step-by-step explanation:

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Answer 2

Answer:

46

Step-by-step explanation:

to find breadth

in a triangle,

h=15cm

b=?

hypotenuse = 17cm

using Pythogerous theorem,

hyptoenues^2= l^2+b^2

17^2 = 15^2 + b^2

289 = 225+ b^2

b^2= 289-225

$b = \sqrt{64}$

b=8

Perimeter of Rectangle = 2(l+b)

2×(15+8)

Perimeter = 46