Question

find The positive root of
$\sqrt{3 {x}^{2} } + 6 = 9$

Answer 1

Solution : 
[tex] \sqrt{3x^2} =3 \\ -\ \textgreater \ \sqrt{x^2} = \sqrt{3} \\ -\ \textgreater \ | x | = \sqrt{3} \\ -\ \textgreater \ x = \sqrt{3}[/tex]

The only positive solution to this is | √3 |