the velocity of an object changes from v1=10i^+4j^+2k^ to v2=4i^+2j^+3k^in 5 sec find the magnitudevof average acceration
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v = v1-v2
= 6î+2j^-k^
acc = v*t = 5(6î+2j^-k^)
= 30i+10j^-5k^
|a| = √ 30²+10²+(-5)²
= √ 900+100+25
=√1025
=32 m/s²
= 6î+2j^-k^
acc = v*t = 5(6î+2j^-k^)
= 30i+10j^-5k^
|a| = √ 30²+10²+(-5)²
= √ 900+100+25
=√1025
=32 m/s²
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