Question

find the principal if the compound interest compounded annually 10% per annum for 3 years is rupees 331​

Answer 1

Answer:

Principal = ₹1000

Step-by-step explanation:

Compound Interest = ₹331

rate (r) = 10%p.a.

time (n) = 3years

Let the Principal = p

CI = p × {(1 + r/100)ⁿ - 1}

=> 331 = p × {(1 + 10/100)³ - 1}

=> 331 = p × {(1 + 1/10)³ - 1}

=> 331 = p × {(10+1/10)³ - 1}

=> 331 = p × {(11/10)³ - 1}

=> 331 = p × {1331/1000 - 1}

=> 331 = p × {1331-1000/1000}

=> 331 = p × 331/1000

=> p = 331 ÷ 331/1000

=> p = 331×1000/331

=> p = 1000